3j^2-26j+16=0

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Solution for 3j^2-26j+16=0 equation:


Simplifying
3j2 + -26j + 16 = 0

Reorder the terms:
16 + -26j + 3j2 = 0

Solving
16 + -26j + 3j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(2 + -3j)(8 + -1j) = 0

Subproblem 1

Set the factor '(2 + -3j)' equal to zero and attempt to solve: Simplifying 2 + -3j = 0 Solving 2 + -3j = 0 Move all terms containing j to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -3j = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -3j = 0 + -2 -3j = 0 + -2 Combine like terms: 0 + -2 = -2 -3j = -2 Divide each side by '-3'. j = 0.6666666667 Simplifying j = 0.6666666667

Subproblem 2

Set the factor '(8 + -1j)' equal to zero and attempt to solve: Simplifying 8 + -1j = 0 Solving 8 + -1j = 0 Move all terms containing j to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1j = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1j = 0 + -8 -1j = 0 + -8 Combine like terms: 0 + -8 = -8 -1j = -8 Divide each side by '-1'. j = 8 Simplifying j = 8

Solution

j = {0.6666666667, 8}

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